Question

factorise 4 x 2 + X 2 + 16 Z2 plus 12 x 2 ​

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

${4x}^{2} + {9y}^{2} + {16z}^{2} + 12xy - 24xy - 16xz \\ {(2x)}^{2} + {(3y)}^{2} - {(4z)}^{2} + 2(2x)(3y) + 2(3y)( - 4z) + 2( - 4z)(2x) \\ {a}^{2} + {b}^{2} + {c}^{2} + 2ab + 2bc + 2ca = {a + b + c }^{2} \\ {2x + 3y - 4z}^{2}$

I have given the answers separately