Question

factorise 4 x square - 16 y square + 8 Y - 1​

Answer 1

$4 {x}^{2} - 16 {y}^{2} + 8y - 1 \\ = 4 {x }^{2} - 1 - 16 {y}^{2} + 8y \\ = (2y) {}^{2} - 1 {}^{2} - 8y(2y - 1) \\ =( 2y + 1)(2y - 1) - 8y(2y - 1) \\ = (2y - 1)(2y + 1 - 8y) \\ = (2y - 1)(1 - 6y)$

Answer: (2y-1)(1-6y)

If you are helped by my answer please follow me and please mark me as brainliest...