factorise 4(x²+1)²+13(x²+1)-12
adwitiy:
X+1 k factor nikalne hai na
kya karna hai iss sum mai
adw...(x²+1) k factor padne he
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4(x²+1)²+13(x²+1)-12
⇒(x²+1)[4(x²+1)+13-12]
⇒(x²+1)(4x²+4+1)
⇒(x²+1)(4x²+5) {ans.}
⇒(x²+1)[4(x²+1)+13-12]
⇒(x²+1)(4x²+4+1)
⇒(x²+1)(4x²+5) {ans.}
Answered by
1
asuming x^2+1=y
than eqation become 4y^2+13y-12=0
4y^2+16y-3y+12=0
4y(y+4)-3(y+4)
(4y-3)(y+4)
put value of y
therfor ans is {4(x^2+1)-3}{x^2+1+4}
than eqation become 4y^2+13y-12=0
4y^2+16y-3y+12=0
4y(y+4)-3(y+4)
(4y-3)(y+4)
put value of y
therfor ans is {4(x^2+1)-3}{x^2+1+4}
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