Question

Factorise 4 y cube + 4 y square - y - 1

Answer 1

Solution :

∴ 4y³ + 4y² - y - 1

= 4y² (y + 1) - 1 (y + 1)

= (y + 1) (4y² - 1)

= (y + 1) {(2y)² - 1²}

= (y + 1) (2y + 1) (2y - 1) ,

which is the required factorization.

Answer 2

Step-by-step explanation:

$\huge\underline\mathfrak\green{Solution}$