Question

factorise -4(y+z)^2+20(y+z) completely

Answer 1

Answer:

-4(y+z)²+20(y+z) = 4(y+z)(-4y-4z+5)

Step-by-step explanation:

-4(y+z)²+20(y+z)

= -4(y+z)(y+z) + 5 × 4(y+z)

= 4(y+z)[-4(y+z)+5]

= 4(y+z)(-4y-4z+5)

Therefore,

-4(y+z)²+20(y+z) = 4(y+z)(-4y-4z+5)

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Answer 2

(-4y - 4z)[y + z - 5]

Step-by-step explanation:

Given:

-4(y + z)² + 20(y + z)

Find:

Factors.

Computation:

⇔ -4(y + z)² + 20(y + z)

⇔ -4(y + z)[(y + z) - 5]

⇔ -4(y + z)[y + z - 5]

⇔ (-4y - 4z)[y + z - 5]

Therefore, (-4y - 4z)[y + z - 5] is a factor of -4(y + z)² + 20(y + z)

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https://brainly.in/question/11963054