Math, asked by winner857, 1 year ago

factorise 44(a^4-5a^3-24a^2)÷11a(a-8)​

Answers

Answered by tilakrvarmapilot7
1

Answer:

=44(a^4-5a^3-24a^2)÷11a(a-8)

=44a^2(a^2-5a-24)÷11a(a-8)       ...........44a^2÷11a=4a

=4a(a^2-8a+3a-24)÷(a-8)​             ...........quadratic equation

=4a(a+3)(a-8)÷(a-8)              ......................(a-8)÷(a-8)=1

=4a(a+3)

Answered by sywathar77gmailcom
0

Answer:

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