Math, asked by riya3383, 1 year ago

factorise 44 x square minus x minus 3​

Answers

Answered by advsanjaychandak
12

Answer:

(4x+1)(11x-3)

Step-by-step explanation:

44x^2-x-3

44x^2-12x+11x-3

4x(11x-3)+1(11x-3)

(4x+1)(11x-3) are the factors

Value of 'x' is;

4x+1=0

x=-1/4

And,

11x-3=0

x=3/11

Thanks

Eid Mubarak

Hope it may helps uh...

#kanika...

Answered by Anonymous
9

Answer:

(4x +1)(11x-3) is the factorised form

Step-by-step explanation:

Given , the equation

44 {x}^{2}  - x - 3 \\  \\   = 44 {x}^{2} - 12x + 11x - 3 \\   \\ = 4x(11x - 3) + 1( 11x - 3) \\  \\  = (4x + 1)(11x - 3)

is the factorised form

If we find the zeroes of this polynomial , they will be : -

4x + 1 = 0 \\   \implies4x =  - 1 \\  \implies \: x =  -  \frac{1}{4}

Or

11x - 3 = 0 \\  \implies11x = 3 \\  \implies \: x =  \frac{3}{11}

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