Math, asked by shikhasejwal80833, 9 months ago

factorise 48 bx^2-75 by^2​

Answers

Answered by tanubera25
3

Answer:

3b(4x+5y)(4x-5y)

Step-by-step explanation:

48 bx^2-75 by^2

=3b(16x^2-25y^2)

=3b(4x+5y)(4x-5y)

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Answered by InfiniteSoul
0

{\huge{\bold{\purple{\bigstar{\boxed{\boxed{\bf{Question}}}}}}}}

factorise 48 b^2x^2- 75 b^2y^2

{\huge{\bold{\purple{\bigstar{\boxed{\boxed{\bf{Solution}}}}}}}}

 3b(16x^2 - 25y^2)

 3b((4b)^2 - (5y)^2)

{\bold{\blue{\boxed{\bf{x^2 - y^2 = (x+y)(x-y)}}}}}

 3b (4b-5y)(4b+5y)

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