Math, asked by poonamagarwal401, 3 months ago

factorise 49/x²-36/y²​

Answers

Answered by grithachinnu86
1

Answer:

49x2−36y249x2-36y2

Rewrite 49x249x2 as (7x)2(7x)2.

(7x)2−36y2(7x)2-36y2

Rewrite 36y236y2 as (6y)2(6y)2.

(7x)2−(6y)2(7x)2-(6y)2

Since both terms are perfect squares, factor using the difference of squares formula, a2−b2=(a+b)(a−b)a2-b2=(a+b)(a-b) where a=7xa=7x and b=6yb=6y.

(7x+6y)(7x−(6y))(7x+6y)(7x-(6y))

Multiply 66 by −1-1.

(7x+6y)(7x−6y)

Answered by anumathsfiles
0

Answer:

Step-by-step explanation:

7² / x² - 6² / y²

= (7/x)² - (6/y)²              this is of the form a² - b² = (a+b) (a-b)

= (7/x + 6/y ) ( 7/x - 6/y)

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