factorise 49 y square - 121
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Answer:121x2 121 x 2 as (11x)2 ( 11 x ) 2 . Rewrite 49y2 49 y 2 as (7y)2 ( 7 y ) 2 . Since both terms are perfect squares, factor using the difference of squares formula, a2−b2=(a+b)(a−b) a 2 - b 2 = ( a + b ) ( a - b ) where a=11x a = 11 x and b=7y b = 7 y . Multiply 7 by −1
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