Question

factorise 49x^2-81y^2​

Answer 1

so lets go......

here is your answer........

using identity.......

$\large{(a+b)(a-b)=asq-bsq}$

comparing this we get

$\large{49xsq-81ysq=(7x+9y)(7x-9y)}$

the factors are

$\large{(7x+9y)(7x-9y)}$

Answer 2

=49x² - 81y²

=(7x)² - (9y )²

using identity

[using a² - b² = (a+b)(a- b)]

=(7x + 9y)(7x-9y)