Question

Factorise 49x^4-(z-x)^4

Answer 1

Step-by-step explanation:

$49 {x}^{4} - {(z - x)}^{4}$

$= {(7 {x}^{2}) }^{2} - {{((z - x)}^{2})}^{2}$

$= (7 {x}^{2} + {(z - x)}^{2} )(7 {x}^{2} - {(z - x)}^{2} )$

$= (7 {x}^{2} - {z}^{2} - {x}^{2} + 2xz)(7 {x}^{2} + {z}^{2} + {x}^{2} - 2xz)$

$= (6 {x}^{2} - {z}^{2} + 2xz)(8 {x}^{2} + {z}^{2} - 2xz)$

I hope it helps you. If you have any doubts, then don't hesitate to ask.