Math, asked by mahimajoshi1414, 4 days ago

Factorise: 49y ^ 2 - 1​

Answers

Answered by ridhimarajesharora
0

Answer:

( 7 − 1 ) ( 7 + 1 )

Step-by-step explanation:

Use the sum-product pattern

4 9 ^2 − 1

49y^2 + 7y - 7y -1

Common factor from the two pairs

4 9 ^2 + 7 − 7 − 1

7 ( 7+ 1 ) − 1 ( 7 + 1 )

Rewrite in factored form

7 ( 7 + 1 ) − 1 ( 7 + 1 )

( 7 − 1 ) ( 7 + 1 )

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Answered by VelvetRosee
0

Answer:

we are to factorize 49y²-1²  , we get (7y+1)(7y-1)

Step-by-step explanation:

given that:

factorize 49y²-1²

there is nothing mentioned in the question above, we may factorize the above equation.

⇒ it can be expressed as 49y²-1²

⇒(7²)y² - 1²

⇒we know that:

a²-b² = (a+b) . (a-b)

so (7²)y² - 1²   =   (7y)² -(1)²

⇒ (7y+1)(7y-1)

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