Math, asked by ujjwalbhatt121, 1 year ago

Factorise:
(4a-1)^2-8a+2
Please fast

Answers

Answered by mysticd
144
Hi ,


( 4a - 1 )² - 8a + 2

= ( 4a - 1 )² - 2 ( 4a - 1 )


= ( 4a - 1 ) [ 4a - 1 - 2 ]

= ( 4a - 1 ) ( 4a - 3 )

Therefore ,

( 4a - 1 ) and ( 4a - 3 ) are the factors .

I hope this helps you.

:)

ujjwalbhatt121: Thanks
mysticd: :)
Answered by simran0601
65
(4a-1)^2-8a+2
=>(16a^2+1-8a)-8a+2
=>16a^2+1-8a-8a+2
=>16a^2-16a+3
=>16a^2-4a-12a+3
=>4a(4a-1)-3(4a-1)
=>(4a-1)(4a-3)
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