Factorise:
(4a-1)^2-8a+2
Please fast
Answers
Answered by
144
Hi ,
( 4a - 1 )² - 8a + 2
= ( 4a - 1 )² - 2 ( 4a - 1 )
= ( 4a - 1 ) [ 4a - 1 - 2 ]
= ( 4a - 1 ) ( 4a - 3 )
Therefore ,
( 4a - 1 ) and ( 4a - 3 ) are the factors .
I hope this helps you.
:)
( 4a - 1 )² - 8a + 2
= ( 4a - 1 )² - 2 ( 4a - 1 )
= ( 4a - 1 ) [ 4a - 1 - 2 ]
= ( 4a - 1 ) ( 4a - 3 )
Therefore ,
( 4a - 1 ) and ( 4a - 3 ) are the factors .
I hope this helps you.
:)
ujjwalbhatt121:
Thanks
Answered by
65
(4a-1)^2-8a+2
=>(16a^2+1-8a)-8a+2
=>16a^2+1-8a-8a+2
=>16a^2-16a+3
=>16a^2-4a-12a+3
=>4a(4a-1)-3(4a-1)
=>(4a-1)(4a-3)
=>(16a^2+1-8a)-8a+2
=>16a^2+1-8a-8a+2
=>16a^2-16a+3
=>16a^2-4a-12a+3
=>4a(4a-1)-3(4a-1)
=>(4a-1)(4a-3)
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