Question

factorise 4a^2+12ab+9b^2_8a_12b

Answer 1

here
4a^2+12ab+9b^2-8a-12b
=(2a)^2+(3b)^2+12ab-8a-12b
=(2a+3b)^2-12ab+12ab-8a-12b
=(2a+3b)^2-4(2a+3b)
=(2a+3b)(2a+3b)-4(2a+3b)
=(2a+3b)[(2a+3b)-4)
=(2a+3b)(2a+3b-4)

Answer 2

$\Large{\underline{\underline{\bf{Ello}}}}$

$4 {a}^{2} + 12ab + 9 {b}^{2} - 8a - 12b \\ \\ {2a}^{2} + 2 \times 2a \times 3b + {(3b)}^{2} - 4(2a + 3b) \\ \\ {(2a + 3b)}^{2} - 4(2a + 3b)\\ \\ = (2a + 3b)(2a + 3b - 4)$

$\Large{\underline{\underline{\bf{Thanks}}}}$