Question

factorise 4a^2-20a+24+6y-9y^4​

Answer 1

Step-by-step explanation:

Reformatting the input :

Changes made to your input should not affect the solution:

 (1): "a2"   was replaced by   "a^2". 

STEP1:Equation at the end of step 1

(22a2 + 20a) - 24

STEP2:

STEP3:Pulling out like terms

 3.1     Pull out like factors :

   4a2 + 20a - 24  =   4 • (a2 + 5a - 6) 

Trying to factor by splitting the middle term

 3.2     Factoring  a2 + 5a - 6 

The first term is,  a2  its coefficient is  1 .

The middle term is,  +5a  its coefficient is  5 .

The last term, "the constant", is  -6 

Step-1 : Multiply the coefficient of the first term by the constant   1 • -6 = -6 

Step-2 : Find two factors of  -6  whose sum equals the coefficient of the middle term, which is   5 .

     -6   +   1   =   -5     -3   +   2   =   -1     -2   +   3   =   1     -1   +   6   =   5   That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above,  -1  and  6 

                     a2 - 1a + 6a - 6

Step-4 : Add up the first 2 terms, pulling out like factors :

                    a • (a-1)

              Add up the last 2 terms, pulling out common factors :

                    6 • (a-1)

Step-5 : Add up the four terms of step 4 :

                    (a+6)  •  (a-1)

             Which is the desired factorization

Final result :

4 • (a + 6) • (a - 1)