Question

Factorise: 4a^2 - 3a - 10​

Answer 1

hey mate here your ans

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Answer:

a =2

Explanation:

Step-1 : Multiply the coefficient of the first term by the constant   4 • -10 = -40  

Step-2 : Find two factors of  -40  whose sum equals the coefficient of the middle term, which is   -3 .

     -40    +    1    =    -39  

     -20    +    2    =    -18  

     -10    +    4    =    -6  

     -8    +    5    =    -3    That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above,  -8  and  5  

                    4a2 - 8a + 5a - 10

Step-4 : Add up the first 2 terms, pulling out like factors :

                   4a • (a-2)

             Add up the last 2 terms, pulling out common factors :

                   5 • (a-2)

Step-5 : Add up the four terms of step 4 :

                   (4a+5)  •  (a-2)

            Which is the desired factorization

because

The first term is,  4a2  its coefficient is  4 .

The middle term is,  -3a  its coefficient is  -3 .

The last term, "the constant", is  -10

Answer 2

You can do this by middle term splitting

4a^2-8a+5a-10
4a(a-2)+5(a-2)
(4a-2)(a-2)

Factors are : (4a-2)(a-2)