Question

Factorise -4a^2+4ab-4ca​

Answer 1

Factors of -4a2 + 4ab – 4ca

Factors of -4a2

-4a2 = -2 × 2 × a × a

Factors of 4ab

4ab = 2 × 2 × a × b

Factors of – 4ca

-4ca = -2 × 2 × c × a

The common factor of -4a2 + 4ab – 4ca are 2, 2 and a.

-4a2 + 4ab – 4ca = (-2 × 2 × a × a) + (2 × 2 × a × b) – (2 × 2 × c × a)

-4a2 + 4ab – 4ca = (2 × 2 × a)(-a + b – c)

-4a2 + 4ab – 4ca = 4a(-a + b -c)