Question

factorise 4a^2+52a-56​

Answer 1

hi mate,

solution:

4a² + 52a - 56 = 4 • (a² + 13a - 14)

Factoring a² + 13a - 14

a² - 1a + 14a - 14

Step-1 : Add up the first 2 terms, pulling out like factors :

a • (a-1)

Add up the last 2 terms, pulling out common factors :

14 • (a-1)

Step-2 : Add up the four terms of step 1 :

(a+14) • (a-1)

Which is the desired factorization

Final result :

4 • (a + 14) • (a - 1)

i hope it helps you.

Answer 2

Answer:

4a² + 52a - 56 = 0

4( a² + 13a - 14) = 0

a² + 13a - 14 = 0

=> a² - a + 14a - 14 =0

=> a( a - 1) +14( a - 1) =0

=> ( a - 1) (a + 14) =0

=> so, a = 1 or a = -14