Question

factorise: 4a^2 - 9b^2 - 16c^2 + 24bc
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Answer 1

Answer:

(2a+3b-4c)(2a-3b+4c)

Step-by-step explanation:

4a^2 - 9b^2 - 16c^2 + 24bc

= (2a)^2 - (3b-4c)^2

= [tex][/tex](2a+3b-4c)(2a-3b+4c)