Question

factorise 4a^2 +9b^2+c^2+12ab+4ac+6bc

Answer 1

Answer:

${4a}^{2} + {9b}^{2} + {c}^{2} + 12ab + 4ac + 6bc$

${(2a)}^{2} + {(3b)}^{2} + {(c)}^{2} + 2.2a.3b \: + 2.2a.c + 2.3b.c$

we know, (a+b+c)^2 = A2 + B2 + c2 + 2ab + 2bc + 2ac

${(2a + 3b + c)}^{2}$

hope it helps