factorise (4a-2b-3c)^2
Answers
Answered by
3
(a+b+c)²=a²+b²+c²+2ab+2ac+2ca
(4a+-2b+-3c)²
= 16a² + 4b² + 9c²+(2×4a×-2b) +(2×-2b×-3c)+(2×-3c×4a)
= 16a²+4b²+9c² -16ab + 12bc -24ca
Similar questions