factorise 4a^4 + 81b^4
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factorise 4a^4 + 81b^44a^4
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Answer:
Factoring: 4a4-81b4
Theory : A difference of two perfect squares, A2 - B2 can be factored into (A+B) • (A-B)
Proof : (A+B) • (A-B) =
A2 - AB + BA - B2 =
A2 - AB + AB - B2 =
A2 - B2
Note : AB = BA is the commutative property of multiplication.
Note : - AB + AB equals zero and is therefore eliminated from the expression.
Check : 4 is the square of 2
Check : 81 is the square of 9
Check : a4 is the square of a2
Check : b4 is the square of b2
Factorization is : (2a2 + 9b2) • (2a2 - 9b2
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