Question

factorise: 4a²-12a+9-49b²​

Answer 1

Answer:

$4 {a}^{2} - 12a + 9 - 49 {b}^{2} \\ = 4 {a}^{2}- 49 {b}^{2} - 12a + 9 \\ = {(2a)}^{2}- {(7b)}^{2} - (12a - 9) \\ = (2a + 7b)(2a - 7b) - 3(4a - 3)$

Answer 2

Answer: (2a+3+7b)(2a+3-7b)

Step-by-step explanation:

4a^2 can be written as (2a)^2

12a can be written as 2(2a)(3)

9 as 3^2

49b^2 as (7b)^2

up to 9 it is similar to (a-b)^2 formula

(2a-3)^2-(7b)^2 which resembles as (a^2 - b^2)

which can be written as (a+b)*(a-b) that's what the answer is