Factorise 4a2 -16b2 +64c2 -32ac
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Answer:
Given:
4a
2
+9b
2
+16c
2
+12ab−24bc−16ac
Use the formula:
(a+b+c)
2
=a
2
+b
2
+c
2
+2ab+2bc+2ca
Simplify the equation.
4a
2
+9b
2
+16c
2
+12ab−24bc−16ac=(2a)
2
+(3b)
2
+(−4c)
2
+2×2×3ab+2×(−4)×3bc+2×(−4)×2ac
=(2a+3b−4c)
2
Thus, the factor of the equation is (2a+3b−4c)
2
.
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