Question

factorise 4a²-9 please!​

Answer 1

Answer:

4a²-9

we know that 9 =3²   and 4a² = (2a)²

(2a)² - 3²    

we can see that this is in the form of a²-b²

a²-b² = (a+b) (a-b)

similarly

(2a)²-3²    

=(2a+3) (2a-3)

hence factorisation of 4a²-9 is (2a+3) (2a-3)

Answer 2

Answer:

(2a+3) (2a-3)

Step-by-step explanation:

4a²-9

=>(2a)²-(-3)²

=>(2a+3) (2a-3)

hope it helps you