Math, asked by prabhjotsingh2438, 4 hours ago

Factorise: 4a²-9b²-2a-3b​

Answers

Answered by ItzAshi
94

Step-by-step explanation:

{\large{\bf{\underline{\orange{Question :→}}}}}

Factorise: 4a² - 9b² - 2a - 3b

{\large{\bf{\underline{\orange{Solution :→}}}}}

The given equation is :

{\bold{\tt{: \:  ⟹ \:  \:  \:  \:  \: 4a²  \: -  \: 9b²  \: -  \: 2a \:  -  \: 3b}}} \\

We can write it as,

{\bold{\tt{:  \: ⟹ \:  \:  \:  \:  \: (2a)²  \: - \:  (3b)²  \: -  \: (2a + 3b)}}} \\

Apply,

: \:  ⟹ \:  \:  \:  \:  \: {\bold{\tt{\fbox{\pink{a²  \: - \:  b²  \: = \:  (a + b)(a - b)}}}}} \\

{\bold{\tt{:  \: ⟹ \:  \:  \:  \:  \: (2a  \: +  \: 3b)(2a \:  -  \: 3b)  \: - \:  (2a \:  + \:  3b)}}} \\

{\bold{\tt{:  \: ⟹ \:  \:  \:  \:  \: (2a  \: +  \: 3b) [(2a  \: - \:  3b) \:  -  \: 1]}}} \\

{\bold{\tt{:  \: ⟹ \:  \:  \:  \:  \: (2a  \: +  \: 3b) (2a \:  -  \: 3b  \: -  \: 1}}}

Answered by studylover001
132

Answer:

Question:→

Factorise: 4a² - 9b² - 2a - 3b

Solution:→

The given equation is :

➡ 4a²−9b²−2a−3b

We can write it as,

➡ (2a)² − (3b)² − (2a+3b)

Apply,

a² - b² = (a + b)(a - b)

➡ (2a + 3b) (2a - 3b) − (2a + 3b)

➡ (2a + 3b) [(2a - 3b) -1 ]

➡ (2a + 3b) (2a - 3b - 1 )

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