Question

factorise
4a2
+ 9b2
+ 4c2
+ 12ab + 12bc + 8ac​

Answer 1

Answer:(2a + 3b + 2c )(2a + 3b + 2c )=(2a + 3b + 2c ) ²

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Answer 2

Answer:

Answer

Given:

4a

2

+9b

2

+16c

2

+12ab−24bc−16ac

Use the formula:

(a+b+c)

2

=a

2

+b

2

+c

2

+2ab+2bc+2ca

Simplify the equation.

4a

2

+9b

2

+16c

2

+12ab−24bc−16ac=(2a)

2

+(3b)

2

+(−4c)

2

+2×2×3ab+2×(−4)×3bc+2×(−4)×2ac

=(2a+3b−4c)

2

Thus, the factor of the equation is (2a+3b−4c