Math, asked by ludirm44, 8 months ago

Factorise 4a2 + 9b2 + c2 - 12ab + 6bc - 4ca using the identity( a+b+c)

Answers

Answered by mohanddr

4

Step-by-step explanation:

4a 2 +9b 2 +c 2 −12ab−6bc+4ac

=(2a) 2 +(3b) 2 +(1c) 2

−2(2a)(3b)−2(3b)(1c)+2(2a)(1c)

=(2a+3b−c) 2

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