Math, asked by pratyayM, 4 months ago

factorise : 4a3-9a² +3a+2​

Answers

Answered by pawansaklani4747
4

Answer:

STEP

1

:

Equation at the end of step 1

(((4 • (a3)) - 32a2) + 3a) + 2

STEP

2

:

Equation at the end of step

2

:

((22a3 - 32a2) + 3a) + 2

STEP

3

:

Checking for a perfect cube

3.1 4a3-9a2+3a+2 is not a perfect cube

Trying to factor by pulling out :

3.2 Factoring: 4a3-9a2+3a+2

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1: 3a+2

Group 2: -9a2+4a3

Pull out from each group separately :

Group 1: (3a+2) • (1)

Group 2: (4a-9) • (a2)

Bad news !! Factoring by pulling out fails :

The groups have no common factor and can not be added up to form a multiplication.

Polynomial Roots Calculator :

3.3 Find roots (zeroes) of : F(a) = 4a3-9a2+3a+2

Polynomial Roots Calculator is a set of methods aimed at finding values of a for which F(a)=0

Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers a which can be expressed as the quotient of two integers

The Rational Root Theorem states that if a polynomial zeroes for a rational number P/Q then P is a factor of the Trailing Constant and Q is a factor of the Leading Coefficient

In this case, the Leading Coefficient is 4 and the Trailing Constant is 2.

The factor(s) are:

of the Leading Coefficient : 1,2 ,4

of the Trailing Constant : 1 ,2

Let us test ....

P Q P/Q F(P/Q) Divisor

-1 1 -1.00 -14.00

-1 2 -0.50 -2.25

-1 4 -0.25 0.62

-2 1 -2.00 -72.00

1 1 1.00 0.00 a-1

1 2 0.50 1.75

1 4 0.25 2.25

2 1 2.00 4.00

The Factor Theorem states that if P/Q is root of a polynomial then this polynomial can be divided by q*x-p Note that q and p originate from P/Q reduced to its lowest terms

In our case this means that

4a3-9a2+3a+2

can be divided with a-1

Polynomial Long Division :

3.4 Polynomial Long Division

Dividing : 4a3-9a2+3a+2

("Dividend")

By : a-1 ("Divisor")

dividend 4a3 - 9a2 + 3a + 2

- divisor * 4a2 4a3 - 4a2

remainder - 5a2 + 3a + 2

- divisor * -5a1 - 5a2 + 5a

remainder - 2a + 2

- divisor * -2a0 - 2a + 2

remainder 0

Quotient : 4a2-5a-2 Remainder: 0

Trying to factor by splitting the middle term

3.5 Factoring 4a2-5a-2

The first term is, 4a2 its coefficient is 4 .

The middle term is, -5a its coefficient is -5 .

The last term, "the constant", is -2

Step-1 : Multiply the coefficient of the first term by the constant 4 • -2 = -8

Step-2 : Find two factors of -8 whose sum equals the coefficient of the middle term, which is -5 .

-8 + 1 = -7

-4 + 2 = -2

-2 + 4 = 2

-1 + 8 = 7

Observation : No two such factors can be found !!

Conclusion : Trinomial can not be factored

Final result :

(4a2 - 5a - 2) • (a - 1)

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