Question

factorise (4b-3c) ^2 - (3b+2c) ^2​

Answer 1

Here's the required answer to your question

Answer 2

Answer:

7b^2-36bc+5c^2

Step-by-step explanation:

(4b-3c) ^2 - (3b+2c) ^2

Using identity:(a-b)^2=a^2-2ab+b^2

:(a+b)^2=a^2+2ab+b^2

= [(4b)^2-2×4b×3c+(3c)^2]-[(3b)^2+2×3b×2c+(2c)^2]

= (16b^2-24bc+9c^2)-(9b^2+12bc+4c^2)

= 16b^2-24bc+9c^2-9b^2-12bc-4c^2

= 7b^2-36bc+5c^2

Hope it's help u!!