Factorise 4k^2+6k-1
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Given: The term 4k^2 + 6k - 1
To find: Factorise the given term
Solution:
- When we find the roots of the given term, we get it as fractions with root in it.
- The question might be: 4k^2 + 6k
- So in this case we can take k as common, we get:
k ( 4k + 6 )
- Now again taking 2 as common, we get:
2k x ( 2k + 3 )
- So the obtained factors are 2k and 2k + 3 for 4k^2 + 6k.
Answer:
So the factors of 4k^2 + 6k are 2k and 2k + 3.
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