Question

factorise 4p^2+2pq^2+p^2q^2+8 pls fasttttt

Answer 1

Step-by-step explanation:

4p²+2pq²+p²q²+8p

4p²+p²q²+2pq²+8p

p²(4+q²)+2p(q²+4)

(p²+2p)(q²+4)

Answer 2

Answer:

We need to factorise (p

2

−2pq+q

2

)−r

2

We have (p

2

−2pq+q

2

)−r

2

=(p−q)

2

−r

2

By using (a

2

−b

2

)=(a−b)(a+b)

Here a=(p−q),b=r

Therefore, (p

2

−2pq+q

2

)−r

2

=(p−q−r)(p−q+r)

Hence, factors are (p−q−r)(p−q+r).

Step-by-step explanation:

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