Question

Factorise 4p^2 - 9q^2​

Answer 1

Answer:

4p²–9q²

=(2p)²–(3q)²

=(2p–3q)(2p+3q)

[∵, a²–b²=(a–b)(a+b)]

Answer 2

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$4 {p}^{2} - 9 {q}^{2} \\ = {(2p)}^{2} - {(3q)}^{2} \\ = (2p + 3q) \: (2p - 3q)$

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What is factorisation ?

In matgematics It's the way of expressing a number as a product of it's factor.

Formula used here for factorising is,

${a}^{2} - {b}^{2} \\ = (a + b)(a - b)$