factorise 4p square+12pq +9q square
Answers
Answered by
10
4p^2 + 12pq + 9q^2
Let us make it in the form of a^2 + 2ab + b^2
(2p)^2 + 2×(2p)(3q) + (3q)^2
= ( 2p + 3q)^2
Alternate method 》》
Product of numbers which are with squared co efficients = 4 × 9 = 36
Coefficient of both variables = 12
We should get two number which gives product as 36 and sum as 36
So the numbers are 6 and 6
4p^2 + 6pq + 6pq + 9q^2
= 2p×( 2p + 3q ) + 3q ×(2p + 3q )
= ( 2p + 3q )(2p + 3q )
= ( 2p + 3q )^2
Let us make it in the form of a^2 + 2ab + b^2
(2p)^2 + 2×(2p)(3q) + (3q)^2
= ( 2p + 3q)^2
Alternate method 》》
Product of numbers which are with squared co efficients = 4 × 9 = 36
Coefficient of both variables = 12
We should get two number which gives product as 36 and sum as 36
So the numbers are 6 and 6
4p^2 + 6pq + 6pq + 9q^2
= 2p×( 2p + 3q ) + 3q ×(2p + 3q )
= ( 2p + 3q )(2p + 3q )
= ( 2p + 3q )^2
Answered by
13
Heya..!!
Question : 4p² + 12pq + 9q²
Answer :
= (2p)² + 2 × 2 × 3 (3q)²
By using the identity
[a² + 2ab + b² = (a+b)²]
= (2p+3q)²
Hence, ur answer is (2p+3q)²
•○● HOPE IT HELPS UH●○•
Question : 4p² + 12pq + 9q²
Answer :
= (2p)² + 2 × 2 × 3 (3q)²
By using the identity
[a² + 2ab + b² = (a+b)²]
= (2p+3q)²
Hence, ur answer is (2p+3q)²
•○● HOPE IT HELPS UH●○•
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