Question

Factorise 4p² + 16pq + 16q² using appropriate identity, then its value is equal to​

Answer 1

Answer:

(2p+4q)²

Step-by-step explanation:

4p²+16pq+16q²

(2p) ²+2*2p*4q+(4q) ²

(2p+4q)²

(2p4q)(2p4q)

Identity used : (a+b)²

Answer 2

Answer:

$\large{(2p + 4q)}^{2}$

Step-by-step explanation:

$\large 4p² + 16pq + 16q²$

$\large {(2p)}^{2} + 2(2p)(4q) + {(4q)}^{2}$

$\large \purple{ {(2p + 4q)}^{2}}$

Identity used -

$\large{(x + y)}^{2} = {x}^{2} + {y}^{2} + 2xy$