Question

Factorise 4p² - 9q²
Please help​

Answer 1

4p²-9q²=(2p)²-(3q)² using identity (a²-b²=(a+b)(a-b) )

Step-by-step explanation:

4p²-9q²=(2p)²-(3q)²

using identity (a²-b²=(a+b)(a-b) )

=(2p+3q) (2p-3q)

Answer 2

Answer:

Step-by-step explanation:

Here you go mate

Step 1

4p² - 9q²  Question

Step 2

4p² - 9q²  rewrite

(2p)^2-(3q)^2

Step 3

(2p)^2-(3q)^2  Apply two squares formula

Answer

(2p+3q)(2p-3q)

Hope this helped