Question

factorise 4p²q²(p+q)²-2pq(p+q)​

Answer 1

Answer:

(4p2+q2-r2)2-(2pq)2=(p2+q2-r2+2pq)(p2+q2-r2-2pq)

Step-by-step explanation:

Given:-

(4p2+q2-r2)2-4p2q2

Now,

This is forming an identity

a2-b2=(a+b)(a-b)

So,

here

a=(4p2+q2-r2)

b=(2pq)2

So,

 (4p2+q2-r2)2-(2pq)2=(p2+q2-r2+2pq)(p2+q2-r2-2pq)

Answer 2

Step-by-step explanation:

2

q

2

(2p+q)

=p

2

q

2

×2p+p

2

q

2

×q

=2p

3

q

2

+p

2

q

3

Hence, the product of p

2

q

2

and 2p+q is equal to 2p

3

q

2

+p

2

q

3

.