Question

factorise: -4pq2r3+8p3q3r2-24rp2q2
$4pq {}^{2} r {}^{3} + 8p {}^{3} q {}^{3} r { }^{2} - 24rp {}^{2} q {}^{2}$
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Answer 1

Answer:

In the given polynomial 3x

2

−x−4,

The first term is 3x

2

and its coefficient is 3.

The middle term is −x and its coefficient is −1.

The last term is a constant term −4.

Multiply the coefficient of the first term by the constant 3×−4=−12.

We now find the factor of −12 whose sum equals the coefficient of the middle term, which is −1 and then factorize the polynomial 3x

2

−x−4 as shown below:

3x

2

−x−4

=3x

2

+3x−4x−4

=3x(x+1)−4(x+1)

=(3x−4)(x+1)

Hence, 3x

2

−x−4=(3x−4)(x+1).

Step-by-step explanation:

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