Question

Factorise [4x - 1\5]^2 - [x + 1\2]

Answer 1

Answer:

(4x-1/5)^2-(x+1/2)^2

(4x-1/5+x+1/2)(4x-1/5-(x+1/2))

(4x+x-1/5+1/2)(4x-x-1/5-1/2)

(5x-2/10+5/10)(3x-2/10-5/10)

(5x+3/10)(3x-7/10)ans

Step-by-step explanation:

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Answer 2

Answer..

→ ${[ 4x\: -\:{\frac{1}{5}}]^{2}} -\:{[ x\: +\:{\frac{1}{2}}]}$

→ ${ 4x\: -\: x\: +\:{\frac{1}{2}}} -\:{\frac{1}{5}} -\:{\frac{1}{5}}$

→ ${ 3x\: +\:{\frac{3}{10}}} -\:{\frac{1}{5}}$

→ ${ 3x\: +\:{\frac{1}{10}}}$

So, Your answer is...${ 3x\: +\:{\frac{1}{10}}}$

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