Math, asked by malikhunny200524, 8 months ago

Factorise 4x^2-11x-20

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Answered by RaviRock1525K
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Answered by Anonymous
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Answer:

(x - 4)  (4x + 5)

Step-by-step explanation:

Reformatting the input :

Changes made to your input should not affect the solution:

(1): "x2"   was replaced by   "x^2".  

Step by step solution :

Step  1  :

Equation at the end of step  1  :

 (22x2 -  11x) -  20

Step  2  :

Trying to factor by splitting the middle term

2.1     Factoring  4x2-11x-20  

The first term is,  4x2  its coefficient is  4 .

The middle term is,  -11x  its coefficient is  -11 .

The last term, "the constant", is  -20  

Step-1 : Multiply the coefficient of the first term by the constant   4 • -20 = -80  

Step-2 : Find two factors of  -80  whose sum equals the coefficient of the middle term, which is   -11 .

     -80    +    1    =    -79  

     -40    +    2    =    -38  

     -20    +    4    =    -16  

     -16    +    5    =    -11    That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above,  -16  and  5  

                    4x2 - 16x + 5x - 20

Step-4 : Add up the first 2 terms, pulling out like factors :

                   4x * (x-4)

             Add up the last 2 terms, pulling out common factors :

                   5 * (x-4)

Step-5 : Add up the four terms of step 4 :

                   (4x+5)  *  (x-4)

            Which is the desired factorization

Final result :

 (x - 4) * (4x + 5)

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