factorise : 4x^2+12xy+9y^2-6x-9y
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Answered by
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4x2 + 12xy - 6x + 9y2 - 9y - 4
Step by step solution :
Step 1 :
Equation at the end of step 1 :
(((((4•(x2))+12xy)+32y2)-6x)-9y)-4
Step 2 :
Equation at the end of step 2 :
((((22x2 + 12xy) + 32y2) - 6x) - 9y) - 4
Step 3 :
Trying to factor by pulling out :
3.1 Factoring: 4x2+12xy-6x+9y2-9y-4
Thoughtfully split the expression at hand into groups, each group having two terms :
Group 1: 9y2-9y
Group 2: 12xy+4x2
Group 3: -6x-4
Pull out from each group separately :
Group 1: (y-1) • (9y)
Group 2: (x+3y) • (4x)
Group 3: (3x+2) • (-2)
Looking for common sub-expressions :
Group 1: (y-1) • (9y)
Group 3: (3x+2) • (-2)
Group 2: (x+3y) • (4x)
Step by step solution :
Step 1 :
Equation at the end of step 1 :
(((((4•(x2))+12xy)+32y2)-6x)-9y)-4
Step 2 :
Equation at the end of step 2 :
((((22x2 + 12xy) + 32y2) - 6x) - 9y) - 4
Step 3 :
Trying to factor by pulling out :
3.1 Factoring: 4x2+12xy-6x+9y2-9y-4
Thoughtfully split the expression at hand into groups, each group having two terms :
Group 1: 9y2-9y
Group 2: 12xy+4x2
Group 3: -6x-4
Pull out from each group separately :
Group 1: (y-1) • (9y)
Group 2: (x+3y) • (4x)
Group 3: (3x+2) • (-2)
Looking for common sub-expressions :
Group 1: (y-1) • (9y)
Group 3: (3x+2) • (-2)
Group 2: (x+3y) • (4x)
Answered by
29
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