Math, asked by rutika1220, 4 months ago

factorise- 4x^2 + 1300x + 1000​

Answers

Answered by manasvinagpal2802
3

Step-by-step explanation:

42+1

300+1000

{\color{#c92786}{-4x^{2}+1300x+1000}}

−4x2+1300x+1000−

4(2−325−250)

{\color{#c92786}{-4(x^{2}-325x-250)}}

−4(x2−325x−250)

Solution

4(x2−325−250)

Answered by Anonymous
1

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