factorise 4x^2+13x+3
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Answer:
The factorisation is ( x - 3 )*( 4x + 1 )
The factors = -3 , -1/4
Step-by-step explanation:
4x² + 13x + 3 =0
=> 4x² + x + 12x + 3 = 0
=> x(4x+ 1) + 3(4x + 1) = 0
=> ( x + 3 ) ( 4x + 1 ) = 0
=> x = -3, -1/4
The factorisation is ( x - 3 )*( 4x + 1 )
The factors = -3 , -1/4
Please brainlist my answer, if helpful!
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