Question

factorise 4x^2-13x-4​

Answer 1

Answer:

Changes made to your input should not affect the solution:

(1): "x2"   was replaced by   "x^2".  

Step by step solution :

STEP

1

:

Equation at the end of step 1

 (22x2 +  13x) -  4  = 0  

STEP

2

:

Trying to factor by splitting the middle term

2.1     Factoring  4x2+13x-4  

The first term is,  4x2  its coefficient is  4 .

The middle term is,  +13x  its coefficient is  13 .

The last term, "the constant", is  -4  

Step-1 : Multiply the coefficient of the first term by the constant   4 • -4 = -16  

Step-2 : Find two factors of  -16  whose sum equals the coefficient of the middle term, which is   13 .

     -16    +    1    =    -15  

     -8    +    2    =    -6  

     -4    +    4    =    0  

     -2    +    8    =    6  

     -1    +    16    =    15  

Observation : No two such factors can be found !!

Conclusion : Trinomial can not be factored

Equation at the end of step

2

:

 4x2 + 13x - 4  = 0

Step-by-step explanation:

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Answer 2

$= > 4 {x}^{2} - 15x - 4 \: \: \: \: \: \: \: \: \\ = > 4 {x }^{2} -16x + x - 4 \\ = > 4x(x - 4) + (x - 4) \\ = > (x - 4)(4x + 1) \: \: \: \: \: \: \: \: \: \: \: \: \: \\ answer....$

$4 {x}^{2} - 13x - 4$

Can't be Factorized....

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