Question

factorise 4x^2/25-9y^2/49​

Answer 1

Step-by-step explanation:

$\frac{4x {}^{2} }{25} - \frac{ 9y {}^{2} }{49} \\ = ( \frac{2x}{5} ) {}^{2} - ( \frac{3y}{7} ) {}^{2} \\ = ( \frac{2x}{5} + \frac{3y}{7} )( \frac{2x}{5} - \frac{3y}{7})$

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Answer 2

Answer:

$\frac{196 {x}^{2} - 225 {y}^{2} }{1225}$

Step-by-step explanation:

$\frac{4 {x}^{2}}{25} - \frac{9 {y}^{2} }{49} = \frac{2{x}}{5}^{2} - \frac{3 {y}}{7}^{2}} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:= \frac{2 {x}}{5} -$

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