Question

Factorise 4x^2+2y^2+x^2y^2+8

Answer 1

factorization.   do it in steps.

First take      4x^2 - y^2 - 3xy   or    [4 (x/y)^2 - 3 (x/y)  - 1] * y^2

                    [ 4 x/y  + 1 ] [ x/y  - 1 * y^2

                    ( 4x + y)  (x - y)

So LET   4 x^2 - y^2 - 3 x y + 2 x - 2 y

                             =  (4x + y + b) (x - y + c)

 Multiply and  compare coefficients, we get   b = 2,  c = 0

So answer   (4x + y +2 ) (x - y) 

Answer 2

Answer:

4x^2+2y^2+x^2y^2+8

4x^2+2y^3+x^4y+8

2(x^2+y^2)+x^4y+8