Question

factorise 4x^2-38x+4​

Answer 1

Answer:

$\longrightarrow \Large\boxed{\mathsf{2\left(2x^2-19x+2\right)}}$

Step-by-step explanation:

GIVEN:

Find the factors of 4x²-38x+4.

SOLUTIONS & SOLVE:

First, rewrite the equation problem.

Multiply the numbers from left to right.

2*2=4

19*2=38

2*2=4

$\displaystyle \mathsf{2*2x^2-2*19x+2*2}$

Then, you have to find the common term of 2.

$\Rightarrow \Large\boxed{\mathsf{2(2x^2-19x+2)}}$

As a result, the final answer is 2(2x²-19x+2).