Question

Factorise 4x^2- 4√7x + 7

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

Step-by-step explanation:

Concept:

The breaking or decomposition of an entity (such as a number, a matrix, or a polynomial) into a product of another entity, or factors, whose multiplication results in the original number, matrix, etc., is known as factorization or factoring in mathematics.

A polynomial or integer is simply resolved into components that, when multiplied together, produce the original or starting polynomial or integer. The factorization method allows us to simplify any algebraic or quadratic equation by representing the equations as the product of factors rather than by expanding the brackets. Any equation can have an integer, a variable, or the algebraic expression itself as a factor.

Given:

The polynomial $4x^2- 4\sqrt{7x} + 7$

Find:

We have to find the $4x^2- 4\sqrt{7}x + 7$

Solution:

Given that  the polynomial $4x^2- 4\sqrt{7}x + 7$

Splitting the middle term

$4x^2-4\sqrt{7x} +7\\4x^2-2\sqrt{7x} -2\sqrt{7x} +7\\2x(2x-\sqrt{7} )-\sqrt{7}(2x-\sqrt{7} )\\ (2x-\sqrt{7} )(2x-\sqrt{7} )$

Hence the polynomial $4x^2- 4\sqrt{7}x + 7$ is $(2x-\sqrt{7} )(2x-\sqrt{7} )$.

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