Question

factorise 4x^2-4x+1
solve it please !​

Answer 1

Answer:

$4 {x}^{2} - 4x + 1$

$4 {x}^{2} - 2x - 2x + 1$

$2x(2x - 1) - 1(2x - 1)$

$(2x - 1)(2x - 1)$

Answer 2

Step-by-step explanation:

4x^2-4x+1=0

4x^2-2x-2x+1=0

2x(2x-1)-1(2x-1)=0

(2x-1)(2x-1)=0

(2x-1)^2=0

x=1/2

Hope it will help you